3.1523 \(\int \frac{1}{\sqrt{2+b x} \sqrt{6+b x}} \, dx\)

Optimal. Leaf size=19 \[ \frac{2 \sinh ^{-1}\left (\frac{1}{2} \sqrt{b x+2}\right )}{b} \]

[Out]

(2*ArcSinh[Sqrt[2 + b*x]/2])/b

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Rubi [A]  time = 0.0049453, antiderivative size = 19, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.105, Rules used = {63, 215} \[ \frac{2 \sinh ^{-1}\left (\frac{1}{2} \sqrt{b x+2}\right )}{b} \]

Antiderivative was successfully verified.

[In]

Int[1/(Sqrt[2 + b*x]*Sqrt[6 + b*x]),x]

[Out]

(2*ArcSinh[Sqrt[2 + b*x]/2])/b

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 215

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSinh[(Rt[b, 2]*x)/Sqrt[a]]/Rt[b, 2], x] /; FreeQ[{a, b},
x] && GtQ[a, 0] && PosQ[b]

Rubi steps

\begin{align*} \int \frac{1}{\sqrt{2+b x} \sqrt{6+b x}} \, dx &=\frac{2 \operatorname{Subst}\left (\int \frac{1}{\sqrt{4+x^2}} \, dx,x,\sqrt{2+b x}\right )}{b}\\ &=\frac{2 \sinh ^{-1}\left (\frac{1}{2} \sqrt{2+b x}\right )}{b}\\ \end{align*}

Mathematica [B]  time = 0.0105344, size = 39, normalized size = 2.05 \[ \frac{2 \sqrt{b x+2} \sin ^{-1}\left (\frac{1}{2} \sqrt{-b x-2}\right )}{b \sqrt{-b x-2}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(Sqrt[2 + b*x]*Sqrt[6 + b*x]),x]

[Out]

(2*Sqrt[2 + b*x]*ArcSin[Sqrt[-2 - b*x]/2])/(b*Sqrt[-2 - b*x])

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Maple [B]  time = 0.006, size = 66, normalized size = 3.5 \begin{align*}{\sqrt{ \left ( bx+2 \right ) \left ( bx+6 \right ) }\ln \left ({({b}^{2}x+4\,b){\frac{1}{\sqrt{{b}^{2}}}}}+\sqrt{{b}^{2}{x}^{2}+8\,bx+12} \right ){\frac{1}{\sqrt{bx+2}}}{\frac{1}{\sqrt{bx+6}}}{\frac{1}{\sqrt{{b}^{2}}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x+2)^(1/2)/(b*x+6)^(1/2),x)

[Out]

((b*x+2)*(b*x+6))^(1/2)/(b*x+2)^(1/2)/(b*x+6)^(1/2)*ln((b^2*x+4*b)/(b^2)^(1/2)+(b^2*x^2+8*b*x+12)^(1/2))/(b^2)
^(1/2)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+2)^(1/2)/(b*x+6)^(1/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 2.05807, size = 65, normalized size = 3.42 \begin{align*} -\frac{\log \left (-b x + \sqrt{b x + 6} \sqrt{b x + 2} - 4\right )}{b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+2)^(1/2)/(b*x+6)^(1/2),x, algorithm="fricas")

[Out]

-log(-b*x + sqrt(b*x + 6)*sqrt(b*x + 2) - 4)/b

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{b x + 2} \sqrt{b x + 6}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+2)**(1/2)/(b*x+6)**(1/2),x)

[Out]

Integral(1/(sqrt(b*x + 2)*sqrt(b*x + 6)), x)

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Giac [A]  time = 1.14252, size = 32, normalized size = 1.68 \begin{align*} -\frac{2 \, \log \left ({\left | -\sqrt{b x + 6} + \sqrt{b x + 2} \right |}\right )}{b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+2)^(1/2)/(b*x+6)^(1/2),x, algorithm="giac")

[Out]

-2*log(abs(-sqrt(b*x + 6) + sqrt(b*x + 2)))/b